Which is the equation of a line that has a slope of -2/3 and passes through point (-3, -1)? y=-2/3x+1.
y=-2/3x+3.
y=-2/3x-1.
y=-2/3x-3

y = -2/3x - 3

Step-by-step explanation:

First, write the equation using the slope. It should look like this: y = -2/3x + b. Next, find the y intercept by plugging in the point. This is what it looks like: -1 = -2/3(-3) + b. Multiply -2/3 by -3 to get 2. This is what it should look like now: -1 = 2 + b. Subtract 3 from both sides to get -3 = b. Go back to your original equation and plug in -3 for b. This is your final equation:

y = -2/3x - 3

Hope this helped! :)

the answer is 8

step-by-step explanation:

3.14 x 8x8

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer