Sausages come in packets of 9. Bread rolls come in packets of 6. Colin wants to buy enough packs of sausages and rolls so that there are an equal number of sausages and rolls. What is the minimum number of sausages and rolls he needs to buy?

This problem is similar to finding least common multiplier (LCM) of 6 and 9.

6 = 2^1 x 3^1

9 = 3^2

=> LCM = 2^1 x 3^2 = 18

=> Minimum number of sausage packets he could buy: N = 18/9 = 2

=> Minimum number of bread roll packets he could buy: N = 18/6 = 3

Hope this helps!

:)

its the fourth option

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐