The Magic Carpet charges $90 for installation and $9 per square yard of carpeting. The Carpeteria's installation price is $50 but the store charges $13 for each square yard. For what number of square yards of carpeting will the cost, including installation, be the same for both stores? 6a) What expression that represents the cost of having Magic Carpet install carpeting: 6b) What expression that represents the cost of having Carpeteria install carpeting: 6c) Write an algebraic equation that represents when the cost of installing carpet by the two companies will be the same: 6d) For what number of square yards of carpeting will the cost, including installation, be the same for both stores? Solve the equation in 1c. Show your work.

The cost of the carpet at Magic Carpet is: 90 + 9*(area of carpet)

The cost of carpet at Carpeteria is: 50 + 13*(area of carpet)

The algebraic expression for which the cost is the same is: 90 + 9*(area of carpet) = 50 + 13*(area of carpet)

The area of carpet for which the cost is the same is: 10 square yard

Step-by-step explanation:

6a) The cost for magic carpet:

This company charges a fixed fee and a price for each square yard of carpeting, therfore the expression for the cost is:

cost = 90 + 9*a

Where a is the area of carpet to be installed.

6)b) The cost for Capeteria:

This company also charges a fixed fee and a price for each square yard of carpeting, so the expression is:

cost = 50 + 13*a.

6) c) The algebraic expression for the cost to be the same in both stores:

90 + 9*a = 50 + 13*a

6) d) We need to solve the expression above for a:

50 + 13*a = 90 + 9*a

13*a - 9*a = 90 - 50

4*a = 40

a = 40/4 = 10

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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