Two classmates, Aisha and Brandon, want to attend two school activities
over the coming weekend. They have one parking pass between them. The
probabilities that the classmates will attend each event are shown in the
table.
Aisha
Brandon
0.90
0.71
Probability of attending
the Saturday activity
Probability of attending
the Sunday activity
0.68
0.89
They decide to let the person more likely to attend both events have the
parking pass. Assuming that attendance at one activity is independent of
attendance at the other, who is more likely to attend both activities?
A. Aisha. She has a 0.61 probability of attending both activities.
B. Brandon. He has a 0.71 probability of attending both activities.
C. Brandon. He has a 0.63 probability of attending both activities.

C. Brandon. He has a 0.63 probability of attending both activities.

Step-by-step explanation:

                 Probability of attending     Probability of attending

                 the Saturday activity          the Sunday activity

Aisha                     0.90                                  0.68

Brandon                 0.71                                  0.89

Given that attendance at one activity is independent of  attendance at the other, the probability that Aisha attends both activities is: 0.9*0.68 = 0.61, and the probability that Brandon attends both activities is: 0.71*0.89 = 0.63

me! what did you put for this question?

step-by-step explanation:

168

step-by-step explanation:

first off, we know that he drove 3.5 hours at a rate of 48 mph.

knowing that, we want to see how many miles he drove all-together.

in this case, we can just multiply 48 by 3.5.

48 * 3.5 = 168