The system of equations y = negative 3 x + 2 and y = one-half x minus 6 is shown on the graph below.

On a coordinate plane, 2 lines intersect around (2.3, negative 4.75).

What is a reasonable estimate for the solution?
(2 and one-third, negative 4 and three-fourths)
(negative 4 and three-fourths, 2 and one-third)
(2 and two-thirds, negative 4 and one-half)
(Negative 4 and one-half, 2 and two-thirds)

2 and one-third, negative 4 and three-fourths

Step-by-step explanation:

the solution is the point at which the system of equations are equal to each other, meaning where they intersect

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°