X-2y = -10
x-3y = -13

x = -4  , y = 3

Step-by-step explanation:

Solve the following system:

{x - 2 y = -10 | (equation 1)

x - 3 y = -13 | (equation 2)

Subtract equation 1 from equation 2:

{x - 2 y = -10 | (equation 1)

0 x - y = -3 | (equation 2)

Multiply equation 2 by -1:

{x - 2 y = -10 | (equation 1)

0 x+y = 3 | (equation 2)

Add 2 × (equation 2) to equation 1:

{x+0 y = -4 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

{x = -4  , y = 3

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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i dont know sorry

step-by-step explanation: