PLEASE THIS IS A MATTER OF PASS OR FAIL I NEED HELP WITH MORE THAN ONE
A principal is organizing a field trip for more than 400 students. She has already arranged the transportation for 295 students. Each school bus has the capacity to transport 35 students.

Which of the following inequalities could be used to solve for x, the number of school buses still needed to transport all of the students?
A.
35x > 695
B.
35x - 295 > 400
C.
35x + 295 > 400
D.
35x > 400

35x + 295 > 400; Option C

Step-by-step explanation:

~ If it is given that x ⇒ the number of school buses... ~

1. From this information it would be that the number of school buses * the number of students able to be held in a school bus ⇒ the number of students that still need to be transported by bus. That would mean 35x ⇒ is the number of students needed to be transported by bus.

2. Of course, there area still the remaining 295 students, who have already been arranged in some sort of transporation vehicle. That would mean that 295 + 35x ⇒ total number of students, provided the number of students is greater than 400. We would compare the two expressions 295 + 35x and 400 by a greater than sign ( > ) such that the expression would be:

35x + 295 > 400; Option C

d

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.