Find the slope-intercept form of the equation of the line that
passes through the point (3, 3) and has slope 5.

y = 5x-12

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

The slope is 5

y = 5x+b

We have a point (3,3) that we substitute in for x and y

3 = 5(3)+b

3 = 15+b

Subtract 15 from each side

3-15 = 15-15+b

b = -12

The equation is then y = 5x-12

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answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer