The vertex of this parabola is at (-4,-1).When the y-value is 0,the x-value is 2.What is the coefficient of the squared term in the parabola equation

  1/36

Step-by-step explanation:

When the coefficient is 1, the function has zeros at -3 and -5, one horizontal unit from the vertex. You want to move the zero to (2, 0), which is 6 units from the vertex. To achieve a horizontal stretch by a factor of 6, the value of x in the function must be replaced by x/6. That would make the coefficient of x^2 be (1/6)^2 = 1/36.

The coefficient of the squared term is 1/36.

where is the figure