Area of DEF = 6 sq ft
Find the area of ABC. Please help I need BOTH green and grey boxes please .

54 ft^2

(54 in green box; 2 in grey box)

Step-by-step explanation:

We have 2 similar triangles, ABC and DEF.

The area of triangle DEF is given as 6 sq ft.

Side BC of triangle ABC measures 12 ft.

The corresponding side to BC in triangle DEF is EF. It measures 4 ft.

That gives us a scale factor from triangle DEF to triangle ABC.

To find the scale factor between two similar polygons, divide the length of a side of the second polygon by the length of the corresponding side of the first polygon.

scale factor = BC/EF = (12 ft)/(4 ft) = 3

The scale factor of side lengths is 3.

The ratio of the areas is the square of the scale factor.

ratio of areas = 3^2 = 9

Now multiply the area of the first triangle (DEF) by the ratio of areas to get the area of the second triangle (ABC).

area of triangle ABC = 9 * (area of triangle DEF)

area of triangle ABC = 9 * (6 sq ft)

area of triangle ABC = 54 sq ft

54 ft^2

(54 in green box; 2 in grey box)

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.