A bag of marbles contains 8 yellow marbles, 6 blue marbles, 4 red marbles, and 2 green marbles. Two marbles are chosen at random, WITHOUT replacement. What is the probability a red marble is chosen and then a blue marble?

6/95

Step-by-step explanation:

First, let's find the total # of outcomes. There are 8+6+4+2 = 20 marbles in the bag. We have 20 options for the first draw, and 19 for the second. 20*19 = 380 total possible outcomes.

Now, let's fin the successful outcomes. There are 4 red and 6 blue marbles, so 4 for the firs tpick and 6 for the second pick. 4*6 = 24 successful outcomes. To find probability, we do successful outcomes/total outcomes, and in this case, that is 24/380, or 6/95. Hope that helps!

Step-by-step explanation:I don't say you have to mark my ans as brainliest but my friend if it has really helped you plz don't forget to thank me...

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )