A store is selling two different types of cheese. One type sells for $3.75 a pound and a second
type sells for $4.55 a pound. How many pounds of the $3.75 cheese would the store need to mix
together with the $4.55 cheese to get a 45-pound mixture that sells for $4.05 a pound (round your
answer to the nearest pound?

  28 pounds

Step-by-step explanation:

Let x represent the amount of $3.75 cheese needed for the mix. Then the total cost of the mix is ...

  3.75x +4.55(45 -x) = 4.05(45)

  -0.80x = 45(4.05 -4.55) = -0.50(45) . . . . . simplify, subtract 4.55(45)

  x = (5/8)(45) = 28.125 . . . . . . . . . . . . . .divide by -0.80

To the nearest pound, 28 pounds of $3.75 cheese would be needed in the mix.

step-by-step explanation:

bob the banana

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116