What is the slope of a trend line that passes through the points (1.3) and (10, 25)?
-15/2
-1/2
22/9
24/7

22/9

Step-by-step explanation :slope of a trend line that passes through the points (1, 3) and (10, 25) is  22/9

Formula of slope(m) for two points is given by:

slope m: y^2-y^1/x^2-x^1

Given the two points:

(1,3) and (10,25)

Substitute these points in the given formula we have;

m= 25-3/10-1

Simplify:

m= 22/9

Therefore, the slope of a trend line that passes through the points (1, 3) and (10, 25) is  22/9

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the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!

i dont know

step-by-step explanation:

umm. i dont know