A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is 70% salt and Solution B is 95% salt. She wants to obtain 50 ounces of a mixture that is 80% salt. How many ounces of each solution should she use?

30 ounces of solution A

20 ounces of solution B

Step-by-step explanation:

x ounces of solution A

y ounces of solution B

x + y = 50

0.7x  ounces  of salt in the solution A

0.95y ounces  of salt in the solution B

0.8*50 = 40 ounces of salt  in 50 ounces of 80% solution

0.7x + 0.95y = 40

x + y = 50

0.7x + 0.95y = 40

x= 50 - y

0.7(50 - y) + 0.95y = 40

35 - 0.7y + 0.95y = 40

0.25y = 5

y = 20 ounces of solution B

x = 50 - y = 50 - 20 = 30 ounces of solution A

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

i believe that the answer is

b. y-1=-2(x-4)

hope this !