Find the sum of all odd integers between 70 and 120

It forms an AP

AP : 71 , 73 , 75 , .................. 119

a = 71

d = 2

= a + (n-1)d

119 = 71 + (n-1)2

n-1 = (119 - 71)/2

n = 24

= n/2 × (a + )

= 24/2 × (71 + 119)

= 12 × 190 = 2280

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!