Moore's law says that the number of transistors in a dense integrated circuit increases by 41\%41%41, percent every year. In 197419741974, a dense integrated circuit was produced with 500050005000 transistors. Which expression gives the number of transistors in a dense integrated circuit in 197919791979?

In 1979 the amount of transistors in a chip was approximately 27865.

Step-by-step explanation:

Since the number of transistors in 1974 was 5000 per chip and it increases at a rate of 41% per year, the number of transistors in a chip per year can be modelled by the following expression:

chips(t) = 5000*(1.41)^(t - 1974)

Therefore in 1979, we have:

chips(1979) = 5000*(1.41)^(1979 - 1974)

chips(1979) = 5000*(1.41)^5

chips(1979) = 27865.4183

In 1979 the amount of transistors in a chip was approximately 27865.

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

i dont know

step-by-step explanation: