First CORRECT ANSWER WILL GET BRAINLIEST! Don’t answer if you don’t know SIMPLE! No guesses or what you think the answer is! None of that. You know what you can do if you have any questions about this problem. I apologize if I come off as rude, I’m on limited time and deleting questions takes away valuable time.

Hints # 2- Use the length of the sides of the square as the base of the triangles.

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Area of Figure : 80 square inches

Step-by-step explanation:

We can only assume that the areas of all 4 triangles are congruent, and with that let us find the area of one of these triangles and the square in the middle of the figure;

Area of 1 Triangle ⇒ 1/2 * base * height = 1/2 * 4 in * 8 in = 16 in^2,

Area of all 4 Triangles ⇒ 4 * 16 = 64 in^2,

Area of Square ⇒ length * width = 4 in * 4 in = 16 in^2

Through the Partition Postulate, we can say the Area of the Figure is ⇒ Area of all 4 Triangle + Area of Square = 64 in^2 + 16 in^2 = 80 square inches;

* Area of Figure : 80 square inches *

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: