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Hint # 2 - Find the sum of the area of the triangle and the area of the rectangle.

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Area of Figure : 864 feet^2

Step-by-step explanation:

If we were to somewhat envelope this figure in a rectangle, we would make sure it is " circumscribed " by dimensions 30 by 36 feet;

Area of Rectangle ⇒ length * width = 30 * 36 = 1080 feet^2,

Now this unshaded portion inside this imaginary rectangle forms two triangles, one with which we have no idea what the dimensions are. Knowing that, let us consider a simpler option; divide the figure into a rectangle and a triangle ⇒ the rectangle with dimensions 18 by 36 feet, the triangle with height 12 feet by base 36 feet;

Area of Triangle ⇒ 1/2 * base * height = 1/2 * 36 * 12 = 216 feet^2,

Area of Rectangle ⇒ length * width = 18 * 36 = 648 feet^2

By the Partition Postulate, the Area of the Figure is ⇒ Area of Triangle + Area of Rectangle = 216 + 648 = 864 feet^2;

* Area of Figure : 864 feet^2 *

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18