A chemistry teacher needs to make 10 L of 36% sulphuric acid solution. The acid solutions available are 30% sulphuric acid and 50% sulphuric acid, by volume. How many litres of each solution must be mixed to make the 36% solution?

7 L and 3 L

Step-by-step explanation:

Given

Solution  has sulphuric acid by volume

Solution sulphuric acid by volume

final solution is of sulphuric acid

Suppose there is and of sulphuric acid of solution and respectively

So, quantity of acid before and after remains same

and total mixture before and after remains same i.e.

Solving  and   we get

So we get and

So, 7 liters from solution 1 and 3 liters from solution 2

- 70

this is the answer for you hope it

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~