What is the probability of getting an even sum less than 7 on one roll of 2 fair cubes

Step-by-step explanation:

When you roll two fair cubes once, the outcomes are given below:

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

Total Number of Outcomes=36

The sum of the outcomes less than 7 are:

2,3,4,5,6

3,4,5,6

4,5,6

5,6

6

Number of Even sum less than 7=9

Therefore:

Probability of getting an even sum less than 7

total of apples - take away four

6-4 = 2

answer is 2 apples