1. Which function has zeros at x = −2 and x = 5?
A.) f(x) = x^2 + 2x − 10
B.) f(x) = x^2 − 2x − 10
C.) f(x) = x^2 + 3x − 10
D.) f(x) = x^2 − 3x − 10

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4