What is the vertex of the quadratic function f(x) = (x-8)(x - 2)?

The zeros of that quadratic are x=8 and x=2 so the axis is right in between at x=(8+2)/2=5

The vertex is the meet of the axis and the parabola, so

(5, f(5))=(5, (5-8)(5 - 2)) = (5, (-3)(3)) = (5, -9)

(5, -9)

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.