The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm. a. Find the probability that an individual distance is greater than 218.40 cm. b. Find the probability that the mean for 25 randomly selected distances is greater than 203.50 cm. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

answer: 323 is how many she has ☃☃⛄❄

step-by-step explanation:

in mathematics, a constraint is a condition of an optimization problem that the solution must satisfy. there are several types of constraints—primarily equality constraints, inequality constraints, and integer constraints. the set of candidate solutions that satisfy all constraints is called the feasible set.

hoped i'm right lol

step-by-step explanation:

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %