Mathematics, 27.05.2020 19:09 emily5400
The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c = 5. The discriminate b2 – 4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. 5. Solve using the quadratic formula. x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction What are the zeros of the function f(x) = x + 5 – 2x2? x = StartFraction negative 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction x = StartFraction negative 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction x = StartFraction 1 plus or minus StartRoot 39 EndRoot Over negative 4 EndFraction
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The number of possible solutions of a polynomial can be found by looking
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Find the image of a(4, -2) after it is reflected over the line y= 2, then reflected over the line x = 2. (-8,6) o (0.-2) o (0,6) (-8, -2)
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Mathematics, 21.06.2019 22:00
Type the correct answer in the box. consider the system of linear equations below. rewrite one of the two equations above in the form ax + by = c, where a, b, and c are constants, so that the sum of the new equation and the unchanged equation from the original system results in an equation in one variable.
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The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5,...
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