If an area of a rectangle with width x can be represented with the expression a(x)=x(14-x), what is the perimeter of the rectangle?
a.) 28
b.) 56
c.) 56-4x
d.) 4x+28

To solve for the perimeter first figure out the length and width from the formula of area for the rectangle
A = LxW
A = (14-X)•X
L = (14-X)
W = X
P = 2L + 2W
P = 2(14-X) + 2(X)
P = 28 - 2X + 2X
P = 28.
The perimeter of the rectangle is A. 28.