A floor has six sections. The total weight supported by the floor at present is 120 pounds.
If the maximum weight that can be supported by the floor is 900 pounds, what is the maximum additional weight that each section of the floor can support. Give the correct answer and the correct equation required for solution.

4.6875 pounds

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

44

step-by-step explanation:

the