Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity.

In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC.

PLEASE HELP I CANT FIGURE THIS OUT AT ALL 50 POINTS AND MARKING U SMARTEST THING!

The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.

Part A: Identify a pair of similar triangles. (2 points)

Part B: Explain how you know the triangles from Part A are similar. (4 points)

Part C: If DB = 9 and DC = 4, find the length of segment DA. Show your work. (4 points)

Part A. Draw a same triangle which is point A to point E.(Triangle that have the same length as point A to point B)

Part B. The triangle from part A are similar because the triangle ∆ADE and ∆ADB are combined to form an isosceles triangle which have 2 equal sides.

Part C. Apply Sine rule.

AD=DA=15.59#

Step-by-step explanation:

part C: <BAD=180°-60°(get from isoceles triangle)-90°=30°

AD/sin60°=BD/sin30°

AD=9/sin30°xsin60°

true

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: