Los números de teléfonos celulares constan de 10 dígitos, ¿cuántos números diferentes se pueden tener si el primer dígito no debe ser 0, 2 ni 4 y el segundo 4, 6 ni 8?

There are 49,000,00,000 possible numbers.

49,000,00,000 números diferentes posibles.

Step-by-step explanation:

If we have n trials, each with m possible outcomes, the total number of possible outcomes is:

In this question:

The first two trials(numbers), 3 digits are not possible in each. So 7 are possible.

The last eight numbers, all 10 digits are possible.

Then

There are 49,000,00,000 possible numbers.

49,000,00,000 números diferentes posibles.

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph