Binh solved this system of equations by graphing.
Binh’s Graph
Binh says the...
Mathematics, 28.05.2020 01:06 biancasamadp3usfw
Binh solved this system of equations by graphing.
Binh’s Graph
Binh says the point of intersection is (0, –3). Which statements identify the errors Binh made? Check all that apply.
Binh listed the coordinates in the wrong order when describing the point of intersection on his graph.
Binh should have graphed the y-intercept of at .
Binh should have graphed the y-intercept of at .
Binh should have graphed the y-intercept of at .
Binh should have found the point of intersection to be .
Answers: 2
Mathematics, 21.06.2019 12:30
Eric drew a scale drawing of a country park. the scale he used was 1 inch = 2.5 yards. the picnic area is 80 yards wide in real life. how wide is the picnic area in the drawing ?
Answers: 1
Mathematics, 21.06.2019 17:40
Which number produces a rationale number when multiplied by 1/5
Answers: 1
Mathematics, 21.06.2019 18:00
Plz a. s. a. p.the table shows the number of male and female contestants who did not win a prize. what is the probability that a randomly selected contestant won a prize, given that the contestant was female? write the probability as a percent. round to the neares tenth, if needed.
Answers: 1
Mathematics, 21.06.2019 19:30
Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.
Answers: 3
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