Identify the restrictions on the variable x^2-4x-32/x+4

x  cannot equal -4

Step-by-step explanation:

(x^2-4x-32)/x+4

Factor the numerator

(x-8) (x+4) / (x+4)

The denominator cannot be zero so

x+4 cannot equal zero

x  cannot be -4

This is a removable hole since we can cancel it in the numerator and the denominator

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation