A tire company produced a batch of 6 comma 000 tires that includes exactly 220 that are defective. a. If 4 tires are randomly selected for installation on a car, what is the probability that they are all good? b. If 100 tires are randomly selected for shipment to an outlet, what is the probability that they are all good? Should this outlet plan to deal with defective tires returned by consumers?

a)

Who represent 0 defective and using the probability mass function we got:

b)

For this case we can conclude that the outlet plan would deal the defectives returned by consumers

Step-by-step explanation:

Let X the random variable of interest "number of defectives", on this case we now that:  

the probability of being defective for this case is given by:

The probability mass function for the Binomial distribution is given as:  

Where (nCx) means combinatory and it's given by this formula:  

Part a

For this case n = 4 and we want to find this probability:

Who represent 0 defective and using the probability mass function we got:

Part b

For this case n = 100 and we want to find this probability:

Who represent 0 defective and using the probability mass function we got:

For this case we can conclude that the outlet plan would deal the defectives returned by consumers

b.-4 units

all you   do is count how many times you move

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)