The absolute value function g(x) = |x − 2| − 1 is translated 3 units right and 4 units up to become g'(x). The quadratic function f(x) graphed below is moved 2 units right and 7 units up to become f'(x). Which of these two transformed functions has a range of y ≤ 3, and what is the vertex of this transformed function?

g'(x) has a range of y ≤ 3, and its vertex is at (1, 3).
g'(x) has a range of y ≤ 3, and its vertex is at (5, 3).
f'(x) has a range of y ≤ 3, and its vertex is at (−4, 3).
f'(x) has a range of y ≤ 3, and its vertex is at (0, 3).

i think it is

step-by-step explanation:

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x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

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x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this