2y'y"=1 , y(0)=2 , y'(0)=1

The left side is the derivative of :

So we can integrate both sides of

Then integrate again to solve for :

With the given initial conditions, we find

The second equation says is either 1 or -1, but in the latter case, we would get in the first equation, which is undefined over the real numbers, so .

So there are two candidate solutions,

However, the second equation doesn't satisfy the initial value of the derivative, since . So the solution is

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

john earns $14.00 for two hours of work.