In a quadrilateral ABCD where AB║DC point O is the intersection of its diagonals, ∠A and ∠B are supplementary. Point M∈BC and point K∈AD , so that O∈MK. Prove that
MO≅KO.

The answer to this question can be described as follows:

Step-by-step explanation:

In Additional A and B implies, that ABCD is a parallelogram. So, there diagonals AC and BD were intersecting.   AKO and CMO are similar to BC, for they are congruent. There are, therefore, congruent of MCO and KAO.  The AOK and COM triangles are at least identical, so these triangles are congruent because the bisects AC are of BD .Then KO and MO are congruent since they are matching congrue sides, that's why MO≅KO is its points.