The Reflexive Property of Equality says:
A. for any numbers a and b, if a = b then b = a
B. for any numbers a, b, and c, if a = b then a – c = b – c
C. for any numbers a, b, and c, if a = b then a + c = b + c
D. for any number a, a = a

A. For any numbers a and b, if a = b then b = a.

Step-by-step explanation:

Examples:

1 = 2 ⇔ 2 = 1

2x + 3t ⇔ 3t + 2x

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

i think it is 70

step-by-step explanation: