Which quadratic equation is equivalent to (x2 - 1)2 - 11(x2 - 1) + 24 = 0?
Ou? _ 110 + 24 = 0 where u =
= (x2 - 1)
o (02)2 - 11(42) + 24 where u =
u = (x2 - 1)
ou? +1 -110 + 24 = 0 where u = (x2 - 1)
0 (02 - 1)2 - 11(42 - 1) + 24 where u = (x2 - 1)

u² - 11u + 24 = 0

Step-by-step explanation:

Given

(x² - 1)² - 11(x² - 1) + 24 = 0

let u = x² - 1, then

u² - 11u + 24 = 0, where u = x² - 1

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)