PLEASE HELP ME FAST!! GIVING MANY POINTS . Show all work

sin(θ) = √65/9

tan(θ) = √65/4

sec(θ) = 9/4

csc(θ) = 9/√65 = (9√65)/65

cot(θ) = 4/√65 = (4√65)/65

Step-by-step explanation:

Let's first define all these trigonometric functions:

- sine (sin) = opposite / hypotenuse

- cosine (cos) = adjacent / hypotenuse

- tangent (tan) = opposite / adjacent

- secant (sec) = hypotenuse / adjacent

- cosecant (csc) = hypotenuse / opposite

- cotangent (cot) = adjacent / opposite

We know that cos(θ) = 4/9, where 4 is the adjacent and 9 is the hypotenuse. We can make this into a right triangle (see attachment), where one of the legs is 4, the hypotenuse is 9, and the last leg is √(9² - 4²) = √(81 - 16) = √65. That means the opposite is √65.

We can now solve for all the rest of the trigonometric functions:

sin(θ) = √65/9

tan(θ) = √65/4

sec(θ) = 9/4

csc(θ) = 9/√65 = (9√65)/65

cot(θ) = 4/√65 = (4√65)/65

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step-by-step explanation:

there is no question content here, but you for the free points! : d