Diameter eg is drawn on circle h and point f is located on the circle such that gf = 8.5 inches. if the radius of the circle is equal to 10 inches , then what is the measure of gf to the nearest degree

50 degrees

Step-by-step explanation:

Theorem: The angle subtended by the diameter is a right angle.

By the Circle Theorem above, the angle at F is a right angle and thus Triangle EGF is a Right Triangle.

We are to determine the measure of GF.

|GE|=|GO|+|OE|=10+10=20 Inch

Using Trigonometry in the second triangle attached

Theorem: Angle at the centre is twice the angle at the circumference.

By the theorem above:

Measure of Arc GF = 2 X

=2 X 25

mGF=50 degrees

Therefore, the measure of GF is 50 degrees (to the nearest degree)

c) the median for town a 30" is greater than the median for town b 25"

step-by-step explanation:

town a, median = q2 = 30

town b, median - q2 = 25

so the median for town a 30" is greater than the median for town b 25"

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: