A store sold 1800 bags in 1985 and 1500 bags in 1986. If they averaged selling 2100 bags per year through 1987, how many

bags were sold in 1987? (Enter numerical values only)

3000 bags

Step-by-step explanation:

In this case we must apply the formula of the mean, which would be the sum of the values divided by the amount of data is the mean:

m = (a1 + a2 ... an) / n

In this case we know the mean, we must know the 1987 data, therefore:

Let x be the number of bags sold in 1987, replacing in the previous equation:

2100 = (1800 + 1500 + x) / 3

2100 * 3 = 3300 + x

x = 6300 - 3300

x = 3000

Therefore, for the average to be a total of 2100 bags in those 3 years, the amount of bag sold in 1987 must have been 3000 bags

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐