A random sample of 147 recent donations at a certain blood bank reveals that 87 were type A blood. Does this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood? Carry out a test of the appropriate hypotheses using a significance level of 0.01. State the appropriate null and alternative hypotheses.

The p value is lower than the significance level of 0.01. So then we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of type A donations differs from 40%, the percentage of the population having type A blood

Step-by-step explanation:

Infomration given

n=147 represent the random sample taken

X=87 represent the people who are type A blood

estimated proportion of people with type A blood

is the value to verify

represent the significance level

z would represent the statistic

represent the p value

Hypothesis to test

We want to verify if type A donations differs from 40% so then the system of hypothesis are:  

Null hypothesis:  

Alternative hypothesis:  

The statistic for this case is given:

(1)  

Replacing the info given we got:

Now we can calculate the p value with this probability:

The p value is lower than the significance level of 0.01. So then we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of type A donations differs from 40%, the percentage of the population having type A blood

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.