A large on-demand video streaming company is designing a large-scale survey to determine the mean amount of time corporate executives watch on-demand television. A small pilot survey of 10 executives indicated that the mean time per week is 12 hours, with a standard deviation of 3 hours. The estimate of the mean viewing time should be within one-quarter hour. The 95% level of confidence is to be used. How many executives should be surveyed?

So the answer for this case would be n=737 rounded up to the nearest integer

Step-by-step explanation:

We have the following info given:

the sample mean

the sample deviation

represent the sample size

The degrees of freedom are given by:

The margin of error is given by this formula:

   (a)

And on this case we have that ME =0.25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

  (5)

The confidence level is 95% and the critical value for this case would be given by , replacing into formula (5) we got:

So the answer for this case would be n=737 rounded up to the nearest integer

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.