The sum of the areas of two circles is 80 square meters. Find the length of a radius of each circle if
one of them is twice as long as the other.
G
What is the radius of the larger circle?

easy peasy  lemon squeasy (l o l)

Step-by-step explanation:

let the radius of one circle be r and the other be R,

there fore,

2πr + 2πR = 80

=> 2π( r + R) = 80

but we know that, R =2r

=> 2 π ( 3r) = 80

=> 3r = 40/π

=> r = 40/3π

taking the value of pi to be 3.14

=> r = 40/9.42

=> r = 4.246

hence the larger radius = 2r => 8.492

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

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