Mathematics, 29.05.2020 00:03 perlamaria01

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of the height of the big locker what is the total volume of one big locker and one small locker

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Answer from: jonathankingsberry52

$0.54\,\,m^3$

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × $\frac{1.2}{2}=0.6\,\,m$ (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= $0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6$

$=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3$

Answer from: TrueKing184

Volume of big locker = 0.36 $m^{3}$

Volume of small locker = 0.18 $m^{3}$

Total volume = 0.54 $m^{3}$

Step-by-step explanation:

We are given the following:

Width of larger locker = 0.5 m

Depth of larger locker = 0.6 m

Height of larger locker = 1.2 m

It is a cuboid like structure and it is well known that Volume of a cuboid structure = $\text{width} \times \text{depth} \times \text{height}$

So, volume of larger locker =

$0.5 \times 0.6 \times 1.2\\\Rightarrow .36m^{3}$

Width of smaller locker = 0.5 m

Depth of smaller locker = 0.6 m

Height of smaller locker = $\dfrac{1.2}{2} = 0.6m$

Volume of a cuboid structure = $\text{width} \times \text{depth} \times \text{height}$

So, volume of smaller locker =

$0.5 \times 0.6 \times 0.6\\\Rightarrow 0.18m^{3}$

Adding both the volumes, Total volume = 0.54 $m^{3}$

Answer from: Quest

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation:

Answer from: Quest

hard

step-by-step explanation: