Point Q is equidistant from AB and AC. What must be true about Q?
Chose from the following
A. It's on the perpendicular bisector of AB
B. It's on the perpendicular bisector of AC
C. BQ=CQ
D. It is on the angle bisector of ∠BAC.

D. It is on the angle bisector of ∠BAC

Step-by-step explanation:

Given that point Q is equidistant from AB and AC. This implies that AB and AC forms an angle BAC i.e <BAC. An equidistant point is a point that has the same distance from two different reference points.

Bisection is the process by which a line or angle is divided into two equal parts. A line that passes through the point of division is called a bisector, which is of equal distance to either of the reference points.

Thus by construction, a point that would be of equal distance to AB and AC is on an angle bisector of <BAC. So that point Q is on the angle bisector of <BAC.

your answer would be 12

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,