X is a normally distributed random variable with mean 57 and standard deviation 19.
What is the probability that X is between 38 and 76?
SALLE
DE
Write your answer as a decimal rounded to the nearest thousandth.

The probability that X is between 38 and 76 is 0.68268.

Step-by-step explanation:

We are given that X is a normally distributed random variable with mean 57 and standard deviation 19.

The z score probability distribution for normal distribution is given by;

                             Z  =    ~ N(0,1)

where, = population mean = 57

            = standard deviation = 19

Now, the probability that X is between 38 and 76 is given by = P(38 < X < 76)

         P(38 < X < 76)  =  P(X < 76) - P(X 38)

         P(X < 76) = P( < ) = P(Z < 1) = 0.84134

         P(X 38) = P( ) = P(Z -1) = 1 - P(Z < 1)

                                                       = 1 - 0.84134 = 0.15866

The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.84134.

Therefore, P(38 < X < 76) = 0.84134 - 0.15866 = 0.68268.

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~