A basketball player is 7 ft tall. He shoots the ball into the basket and the path of the

ball makes a quadratic equation. This could be shown with the equation h(t) == 15t^2+ 30t+7

where t is the time in seconds after the ball was shot and h is the height. What will the

ball's maximum height be?

52

Step-by-step explanation:

Given the the equation h(t) =- where t is the time in second

So to find the ball's maximum height we can apply the vertex formula:

t=  

to find the "x" value of the vertex, then plug that value into the original equation as a substitute for "x".

Standard quadratic form is:

=> a=15, b=30 in our given equation

<=> t =

When t =-1 we have h(t) = = 52

So the ball's maximum height is:  52

Hope it will find you well.

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft

step-by-step explanation: