: Part A The equation of a circle C is (x+2)2+(y−7)2=36. What is its center (h, k)? A (−2,−7) B (−2,7) C (2,−7) D (2,7) Part B What is the radius (r) of the circle C ? r= .

Centre = (-2,7) B

radius = 6

Step-by-step explanation:

The general formula for finding the equation of a circle is expressed as shown:

(x-h)²+(y-k)² = r² where (a,b) is the centre and r is the radius of the circle

Given the equation of the circle C in question (x+2)²+(y−7)²=36. We will compare the given equation to the general equation.

On comparison;

-h = 2

h = -2

-k = -7

k = 7

r² = 36

r = √36

r = ±6

From the answers gotten, it can be inferred that the centre of the circle (h,k) is (-2,7) and the radius of the circle is 6.

Radius of a circle cannot be a negative value so we will ignore the negative value of 6.

7

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