Which polynomial expression represents a sum of cubes?

 (6+s)(s^2-6s+36)

Step-by-step explanation:

We have general formula for sum of cube which is

a^3+b^3=(a+b)(a^2+b^2-ab)

Here, we have a=s and b=6

on substituting the values in the formula we will get

6^3+s^3=(6+s)(s^2+6^2-6s)

After simplification we will get

6^3+s^3=(6+s)(s^2+36-6s)

After rearranging the terms we will get

6^3+s^3=(6+s)(s^2-6s+36)

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

3+x

step-by-step explanation: