A ball is projected in to the air. its height at the time t is given by the equation h=-16t^2+100t+2. solve for the time as which the height will be 12 feet. show your work and explain the steps you used to solve. round your answer to the nearest hundredth.

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

70.30

step-by-step explanation:

the answer to question 1 is -8, 28.

step-by-step explanation: