Please help!
In Circle o, pa and pb are tangents. The figure is not drawn to scale.
A. prove that APO=~ BPO
B. find m BOD for m AOP 64. Explain your reasoning

Step-by-step explanation:

In ΔAPO and ΔBPO,

     ( Length of tangents from an external point to a circle are equal)

     ( Radii of same circle)

     ( Common side)

∴ ΔAPO = ΔBPO  (SSS Congruence) ---------------(1)

Given that, ∠AOP = 64°

∠AOP = ∠BOP  [ From (1) ]

⇒∠BOP = 64

Now,

∠BOP + ∠BOD = 180°  ( Linear Pair)

             ∠BOD = 180 - 64  (∵ ∠BOP = 64°)

          ∴ ∠BOD = 116°

Hope that helps!!

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